Question: Problem 28 An automatic lathe produces rollers for roller bearings, and the process is monitored by statistical process control charts. The central line of the

Problem 28 An automatic lathe produces rollers
Problem 28 An automatic lathe produces rollers
Problem 28 An automatic lathe produces rollers for roller bearings, and the process is monitored by statistical process control charts. The central line of the chart for the sample means is control as established by samples of size 5. The upper and lower specifications for the diameter of the rolers are (8.80 +0.25) and (8.80 0.25) mm, respectively, Click the icon to view the table of factors for calculating three-sigma limits for the x-chart and R-chart. a. Calculate the control limits for the mean and range charts. The UCLp equals Immand the LOlp equals mm. (Enter your responses rounded to two decimal places.) More Info Factors for calculating three-sigma limits for Factor for R-Chart Size of Sample Factor for UCL and LCL (n) for x-chart (A2) 2 1 880 3 1.023 4 0.729 5 0.577 8 0.483 7 0.419 8 0373 9 0.337 10 0.306 0 0 0 0.070 0.136 0.184 0.223 Print Done Enter your answer in the edit fields and then click Check Answer 3 parts remaining Clear All Question Help statistical process control charts. The central line of the chart for the sample means is set at 6.80 and for the mean range at 0.2 mm. The process is in Gameter of the tollers are (880 -0.25) and (8.80 -0.25) mm, respectively, xchart and R-chart nded to two decimal places.) 1 More Info Factors for calculating throw-sigma limits for the x-chart and R-chart Size of Sample Factor for UCL and LCL Factor for LCL for Factor for UCL for In) for X-chart (A2) R-Chart (D) R-Chart (DA) 2 1.880 0 3.267 3 1,023 0 2575 4 0.729 0 2282 5 0.577 0 2.115 5 0483 D 2004 0.419 0.075 1924 8 0.373 0.136 1.864 9 0337 0.184 1.816 10 0.30 0.223 1777 Print Done Chara ChickAnswer *** do DIE DO US + S Z 6 8 9 0 delete y

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