Question: Python 3 Programming Based on the BFS code given in attachment, allow user to create their own graph by entering vertices and edges of the

Python 3 Programming

Python 3 Programming Based on the BFS code given in attachment, allow

Based on the BFS code given in attachment, allow user to create their own graph by entering vertices and edges of the graph

1. Use the graph information entered by user to implement DFS traversal, let user specify the source node and your code should print the traversal order.

2. Use the concept of traversal learn in BFS, create a GUI to implement DFS search using class based object.

class graphBFS (object) def init (self,graph): self.graph graph self.visited - [1 self.visitQueue[ def bfs (self, sourceNode, targetNode) self.visited - [1 self.visitQueue[ self.visited.append (sourceNode) self.visitQueue.append (sourceNode) found False while self.visitQueue and found is False: sourceNode = self.visitQueue [O] self.visitQueue.remove (sourceNode) print (sourceNode) Eor adjacent in self.graph [sourceNode]: if adjacent not in self.visited: self.visitQueue.append (adjacent) self.visited.append (adjacent) if adjacent is targetNode: print (adjacent) found = True break if found is False: print ("Item not found!") BFSgraphBFS ( E:'D'1 BFS.bfs 'A, F) class graphBFS (object) def init (self,graph): self.graph graph self.visited - [1 self.visitQueue[ def bfs (self, sourceNode, targetNode) self.visited - [1 self.visitQueue[ self.visited.append (sourceNode) self.visitQueue.append (sourceNode) found False while self.visitQueue and found is False: sourceNode = self.visitQueue [O] self.visitQueue.remove (sourceNode) print (sourceNode) Eor adjacent in self.graph [sourceNode]: if adjacent not in self.visited: self.visitQueue.append (adjacent) self.visited.append (adjacent) if adjacent is targetNode: print (adjacent) found = True break if found is False: print ("Item not found!") BFSgraphBFS ( E:'D'1 BFS.bfs 'A, F)

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