Q$1)$ From Fig$\mathrm{.}1$:

Given that:

Fluid: water

Neglect the gravitational effect

Incompressible fluid $($constant $)$

The force acting on the $x-$direction, $F_x=-3000N$

Area at point $1,A_1=0\mathrm{.}05m^2$

Area at point $2,A_2=0\mathrm{.}03m^2$

Velocity at point $2,u_2=6\mathrm{.}5\frac{m}{s}$

Calculate:

i$.$ The pressure at point $1,p_1(\frac{N}{m^2}).$

ii$.$ The force acting on the $y-$direction, $F_y(N).$

Ans check: $)=44800\frac{N}{m^2}.F_w=(2200(N)$