Question: Q1 : Perform Steady state Analysis , make sure you are making Steady state Analysis . In this project each group is going to study

Q1 : Perform Steady state Analysis , make sure you are making Steady state Analysis .Q1 : Perform Steady state Analysis , make sure you are making

In this project each group is going to study the reaction in a continuous stirred-tank reactor (CSTR). As you have seen in the course, CSTR's can operate continuously and provide several advantages. The CSTR in this project is jacketed, none adiabatic and it is not isothermal. A schematic of our process is shown in the figure in bellow. Reaction in the reactor For A we have A+BC with a rate dA/dt=r(t)=CACnk0etatk0=1.01015min4andEa/R=8330.1KdH/dt=Hmaisionf(t)Hmacina=483.6kllimolofC Isobaric molar heat capacity of ACF=29.38Jmol1K1 sobaric molar heat capacity of 8CF=28.84J1mol1K1 Steady-state analysis: - Show how steady states are solutions to a system of nonlinear algebraic equations - Solve a system of nonlinear algebraic equations using MATLAB Unsteady-state analysis Apply a step increase in CN of a magnitude of 0.2mole/m3 and keep C2 unchanged Use the information in the lectures to demonstrate how the transient behavior of the reactor is a solution to a system of nonlinear ordinary differential equations. - Solve a system of nonlinear ordinary differential equations using finite differences. - Write and run a MATLAB to find the solution. Use these data: - Flowrates F1 ( liters/min) =20, F2 (liters/minutes) =10F ( cooling water )= first 3 digits of the 1D of the leader plus 50 . - Concentrations Cay=4 moles/liters Cn=3 Moles/liters - Temperatures T1=300KTx=273%K - Volume of the reactor v (uters) = (the last 3 digits of the 10 of the group leader. If it is less than 200L please add 100L If it is greater than 500 please subtract 250L - Volume of the jacket 20 liters. - Total area for heat transfer 0.0620m2 - Heat transfer coefficient U is estimated to 1000J/K/s/m2 - Stream Volumetric Enthalpies: H1, H2, HE, HX [Joules/liter] - All intial conditions for the concentrations in the reactor are set to zero. - For A we have dA/dt=r(t)=CAC0k0e4a/r - k0=1.01010min1 and Ea/R=8330.1K - dH/dt=Hmactosr(t) - Hramefine=483.6kJimot of C - isobaric molar heat capacity of ACF=29.38Jmol1K1 - Isobaric molar heat capacity of BCF=28.84Jmol1K1 - Isobaric molar heat capacity of CCp=75.20Jmol1K1

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