Q3 D kc =0 ay 25 ( y= top) = orcantual or FD/BD ac ( )1 = 2 ) = 0 C=40 C = 100 20 =0 DX = Dy=h 2 4 4 + K h ) ( ij = 0 egh intury nodes Corners : - 2 R/C , pick one Bottom boundry bex > ac = 0 20 > c = 1003. [5-0 points] Compute and plot the steenlystate distribution of concentration for the tank shown in Figure l. The PDE governing this system is we n('j"+)es=e (a) ("11:3 3:33;? and the boundaryr conditions are as shmvn. Employ a value of {15 for D and Ill for In. Use a small enough u]: = day = flu-5 so that your answer does not depend on the value. The wall boundary mnditiom; correspond to zero deriwitive in the direction normal to the well. \f