Question: Solve the initial value problem d2x 0.2 +1.2 + 2x = 5cos4t dx dt2 dt Where x (0) = and x'(0) = 0

Solve the initial value problem d2x 0.2 +1.2 + 2x = 5cos4t 

Solve the initial value problem d2x 0.2 +1.2 + 2x = 5cos4t dx dt2 dt Where x (0) = and x'(0) = 0

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