Question $2$: Underline the correct answer between the parentheses.

Marks$)$

A frequency range from $850MHz$ to $900MHz$ will be used to transmit multiple channel data, each

with a bandwidth of $20KHz.$ Hence, by using the concept of $($CDMA $-$ TDMA $-$ FDMA $-$ HDMA$)$

it can be split into $(2\mathrm{.}5-25-250-2500)$ channels.

If $($CDMA $-$ TDMA $-$ FDMA $-$ HDMA$)$ concept is used, this will enable $10$ users to use the same

channel, each for a dedicated time of $0\mathrm{.}6ms,$ which means every user must wait for

$-5\mathrm{.}4ms-54ms)$ before using the same channel again.

As a result of using these $2$ concepts together, the total number of users who can simultaneously

use this range is $(25-2500-250-25000).$