Solution cont... BDC} 3x k = 0 (Carry overlast step) Now that it is quadratic in form we can say: a = D , b = [:1 , C = [3 Now plugging into the quadratic formula we get: Wim C] For x to be a real solution, 3x needs to be equal to a real nonnegative number. Thus we only need to determine when the discriminant in nonnegative. :20 k: (g Solve Quadratic in Form 2 :---: u + be...su + C = 0 Problem: For what values of k does the equation 9x 3x +1 = k has one or more real solutions? a [link Get the same base and try getting the equation to be quadratic in form in order to solve. Solution: 9x 3'\"1 = k 3- 3x+1 k =