Solve $$numerically by $$Stiffness $$Matrix $$Method$,$consider $$all $$bars $$as $$axially $$rigid$,$ so $$that $$axial $$deformation $$is $$neglected$.$Keep $$in $$mind $$the $$lateral $$displacements $$are $$the $$same $$for $$the $$horizontal $$bar $$due $$to $$be $$axially $$rigid$,$also$,$ vertical $$displacement $$is $$zero $$for $$node $$A$,$ but $$not $$for $$B $$because $$the $$bar $$is $$inclined$.$I $$know $$this $$because $$the $$frame $$was $$modeled $$in $$a $$software $$before$.$ Do numerical calculations with the data provided. Do $$not $$skip $$any $$hand $$calculations at least until you calculate all the displacement,$$ thanks $$in $$advance$.$

$($:$\frac{EA}{L}\}E=$ constant

$$ local direction of frame