Question: sta and Graph Analysis Name: Lab Partner or the reaction: CV + NaOH -- colorless products The rate law is Ratek[CVT (NaOH For both the

 sta and Graph Analysis Name: Lab Partner or the reaction: CV
+ NaOH -- colorless products The rate law is Ratek[CVT (NaOH For
both the kinetic runs today, the NaOH] >> CV), so that the

sta and Graph Analysis Name: Lab Partner or the reaction: CV + NaOH -- colorless products The rate law is Ratek[CVT (NaOH For both the kinetic runs today, the NaOH] >> CV), so that the [NOM] remains virtually constant throughout the experiment. Therefore, the rate law can be written as Rate -k[CV), wherek-k[NaOHP 1) Looking at the various graphs and determining which are most linear, determine the order of the reaction with respect to the crystal violet. (CV). What is the value of "c? 2) Look at the graphs for Run I and Run 2 that pertain to the order of the reaction with respect to [CV The slope of the graphs is equal to k', which is itself equal to k[NaOH). In the first run. (NO) 0.010 M after dilution, and in the second run, [NaOH) - 0.020 Mafter dilution. Use this information to find the value for "y". Keep in mind, this is experimental data, so round off to the clones whole number 3) Using the fact that k-k[NaOH), and referring to the two graphs used in calculation 2, determine the value for k for both runs, and find an average value for k, including units. 4) Write the rate law, and give the average value for k, including units. C, 8/18 OF 06 05 Absorbance 05 -0.7- 0.4 20 10 15 Time (me) (A10.10 Ay 0.002) Cheer 00HWA Se DY: -0.3510 Com-1000 RUSE 0011 -1.1- 20 25 10 15 Time (min) (22.56,-0.736) 2,5 Crew MA 1411 DY 145 Conson VSE DOT 20 Run I 1.5 20 10 55 Time (min) 0.35 Utor TA mm 0.1 by 357 Con 0.00 WE GOO re C 0.30 Absorbance 020 15 20 23 10 Time (min 20 10 16 Time (mind -1.0 - 12 -14 RUN 2 LIWA WA (63166 01 Ca. RUSED HO 15 Time (min) 0

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