started 50ML End 102ml PROCESSING THE DATA 1. Determine the volume of NaOH added at the equivalence point. 11.gome 2. Calculate the number of moles of NaOH used. moles= volymex M (0.01190L) x (0.100M) = 0.00119 mules NaOH 3. See the equation for the neutralization reaction given in the introduction. Determine the number of moles of HCl used. mole HC1= mol NaOH x 1 mol HC/ 4. Recall that you pipeted out 10.0 mL of the unknown HCl solution for the titration. Calculate the HCl concentration. DATA AND CALCULATIONS Concentration of NaOH NaOH volume added before largest pH increase aOH volume added after largest pH increase Volume of NaOH added at equivalence point Moles NaOH Moles HCI Concentration of HCI Average [HC] volume of Nast-11.90ml 700011901 bank - Yolutne Y M Trial 1 0.100 11.90 0000119 10000119 0.119 M 0.100 mL mL mL mol mol Trial 2 mol/L 11.90 0.00119 0.00119 0.119 M mL mL mL mol mol mol/L M moles Naotte moles HCl mule HC1 = mol Naol x Imol HCl Imel Nagt 557