Suppose a marketing company randomly surveyed 423 households and found that in 258 of them, the...

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Suppose a marketing company randomly surveyed 423 households and found that in 258 of them, the woman made the majority of the purchasing decisions. Construct a 91% confidence interval for the population proportion of households where the women make the majority of the purchasing decisions. = 82 11 Margin of Error: E = We are 91% confident that the proportion of households in the population where women make the majority of purchasing decisions is between and Suppose a marketing company randomly surveyed 423 households and found that in 258 of them, the woman made the majority of the purchasing decisions. Construct a 91% confidence interval for the population proportion of households where the women make the majority of the purchasing decisions. = 82 11 Margin of Error: E = We are 91% confident that the proportion of households in the population where women make the majority of purchasing decisions is between and

Answer rating: 100% (QA)

Answer 1 The proportion of households in the population where women make the majority of purchasing decisions is p 258423 06093 A 91 confidence interv... View the full answer