Suppose a program, initially loaded into RAM, contains $100$ instructions $($all

instructions are register based$).$ When it is run, CPU reads$/$finds $80$

instructions from cache memory. For the remaining instructions, CPU has to

access RAM.

In such case, the Hit ratio of Cache for the program would be $80\%,$ means

that $80$ out of $100$ instructions are found in cache.

Suppose a program, initially loaded into RAM, contains $300$ instructions $($all

instructions are register based$).$ When it is run, CPU reads$/$finds $250$

instruction from cache memory. For the remaining instructions, CPU has to

access RAM. Calculate Hit Ratio: $(250/300)$x $100=83\mathrm{.}33\%$

What would be the Miss Rate?