suppose that in each individual of a large population there is a pair of genes, each...

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suppose that in each individual of a large population there is a pair of genes, each of which can be either x or X, that controls eye color: those with xx have blue eyes, while heterozygotes (those with Xx or XX) and those with XX have brown eyes. The proportion of blue-eyed individuals is p² and of heterozygotes is 2p(1 p), where 0 < p < 1. Each parent transmits one of its own genes to the child; if a parent is a heterozygote, the probability that it transmits the gene of type X is. Assuming random mating, show that among brown-eyed children of brown-eyed parents, the expected proportion of heterozygotes is 2p/(1+2p). Suppose Judy, a brown-eyed child of brown-eyed parents, marries a heterozygote, and they have n children, all brown-eyed. Find the posterior probability that Judy is a heterozygote. and the probability that her first grandchild has blue eyes. suppose that in each individual of a large population there is a pair of genes, each of which can be either x or X, that controls eye color: those with xx have blue eyes, while heterozygotes (those with Xx or XX) and those with XX have brown eyes. The proportion of blue-eyed individuals is p² and of heterozygotes is 2p(1 p), where 0 < p < 1. Each parent transmits one of its own genes to the child; if a parent is a heterozygote, the probability that it transmits the gene of type X is. Assuming random mating, show that among brown-eyed children of brown-eyed parents, the expected proportion of heterozygotes is 2p/(1+2p). Suppose Judy, a brown-eyed child of brown-eyed parents, marries a heterozygote, and they have n children, all brown-eyed. Find the posterior probability that Judy is a heterozygote. and the probability that her first grandchild has blue eyes.

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1 Among browneyed children of browneyed parents both parents must be heterozyg... View the full answer