Question: Suppose we have a 32MB byte addressable memory built from 16Kx8 RAM chips. How many bits are needed for the address? How many chips are

Suppose we have a 32MB byte addressable memory built from 16Kx8 RAM chips.

  1. How many bits are needed for the address?
  2. How many chips are needed?
  3. How many bits are needed to choose the chip?
  4. How many bits are needed to choose the location/offset on the chip?
  5. If high-order interleaving is used, which of the address bits are to choose the chip and which are to choose the location on the chip?
  6. If low-order interleaving is used, which of the address bits are to choose the chip and which are to choose the location on the chip?
  7. If high order interleaving is used, where would address 0x3AD69 be located? (Give your answer in the format: chip 0xPP, btye 0xQQQ)
  8. If low order interleaving is used, where would address 0x3AD69 be located? (Give your answer in the format: chip 0xPP, btye 0xQQQ)

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