Question: table [ [ table [ [ Shear Distance ] , [ ( mm ) ] ] , Area ( mm ^ 2 )

\table[[\table[[Shear Distance],[(mm)]],Area(mm^2),\table[[20Kg Sample],[displacement],[gauge],[reading(mm)]],Shear force (N),\table[[Shear],[stress(Mpa)]]],[1,100\times 99,27,,],[2,100\times 98,41,,],[3,100\times 97,52,,],[4,100\times 96,61,,],[5,100\times 95,68,,],[6,100\times 94,74,,],[7,100\times 93,77,,],[8,100\times 92,80,,],[9,100\times 91,84,,],[10,100\times 90,84,,],[11,100\times 89,83,,],[12,100\times 88,73,,],[13,100\times 87,71,,]]
Given the above shear box laboratory test readings, calculate the shear force and Shear stress,draw a graph of shear stress vs shear displacement analyse the results and to het the internal angle of friction and cohesion
Given the Ring factor of 0.01184knmm
\ table [ [ \ table [ [ Shear Distance ] , [ ( mm

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