Question: The distribution coefficient, k = concentration in hexanes/concentration in water, between hexanes and water for solute A is 7.5. a) What weight of A would
The distribution coefficient, k = concentration in hexanes/concentration in water, between hexanes and water for solute A is 7.5.
a) What weight of A would be removed from a solution of 10 g of A in 100 mL of water by a single extraction with 100 mL of hexanes?
b) What weight of A would be removed by four successive extractions with 25-mL portions of hexanes?
c) How much hexanes would be required to remove 98.5% of A in a single extraction?
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To solve this problem we need to apply the principle of distribution or partitioning which states that a solute will distribute itself between two imm... View full answer
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