The energy equation for this problem must take into account several approximations. We will neglect viscous dissipation since the rod is solid. The only velocity is in the z-direction and that velocity will be constant. There will be no temperature gradient in the angular or radial directions. With that in mind, the energy equation looks like: * 3T - pc,(v. 37) k z The boundary conditions are: z=0 T = T b z = Z, Solving gives: T=T T = T+ T=-Ca C. ( =*) EXP(-1 + ) + C exp -z 0 m exp T-T b m VZ 00 *exp(-x + =]]