The following are quality control data for a manufacturing process $at$ Kensport Chemical Company. The data show the temperature $in$ degrees centigrade $at$ five points $in$ time during a manufacturing cycle.$\frac{?}{b}$

egin$\{tabular\}\{|c|c|c|\}\frac{?}{h}$

line Sample & $\frac{?}{(\stackrel{}{?}\frac{?}{\text{b}\text{o}\text{l}\text{d}\text{s}\text{y}\text{m}\text{b}\text{o}\text{l}\{x\}}\frac{?}{?})}$ & $\frac{?}{(\frac{?}{\text{b}\text{o}\text{l}\text{d}\text{s}\text{y}\text{m}\text{b}\text{o}\text{l}\{R\}}\frac{?}{?})}\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}1$ & $95\mathrm{.}72$ & $1\mathrm{.}0\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}2$ & $95\mathrm{.}24$ & $0\mathrm{.}9\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}3$ & $95\mathrm{.}18$ & $0\mathrm{.}8\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}4$ & $95\mathrm{.}42$ & $0\mathrm{.}4\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}5$ & $95\mathrm{.}46$ & $0\mathrm{.}5\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}6$ & $95\mathrm{.}32$ & $1\mathrm{.}1\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}7$ & $95\mathrm{.}40$ & $1\mathrm{.}0\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}8$ & $95\mathrm{.}44$ & $0\mathrm{.}3\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}9$ & $95\mathrm{.}08$ & $0\mathrm{.}2\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}10$ & $95\mathrm{.}50$ & $0\mathrm{.}6\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}11$ & $95\mathrm{.}80$ & $0\mathrm{.}6\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}12$ & $95\mathrm{.}22$ & $0\mathrm{.}2\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}13$ & $95\mathrm{.}60$ & $1\mathrm{.}3\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}14$ & $95\mathrm{.}22$ & $0\mathrm{.}6\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}15$ & $95\mathrm{.}04$ & $0\mathrm{.}8\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}16$ & $95\mathrm{.}72$ & $1\mathrm{.}1\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}17$ & $94\mathrm{.}82$ & $0\mathrm{.}6\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}18$ & $95\mathrm{.}46$ & $0\mathrm{.}5\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}19$ & $95\mathrm{.}60$ & $0\mathrm{.}4\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}20$ & $95\mathrm{.}74$ & $0\mathrm{.}6\frac{\frac{?}{?}}{?}$

$\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}\frac{?}{\text{h}\text{l}\text{i}\text{n}\text{e}}\frac{?}{e}$

$nd\{tabular\}$

UCL $=$

$LCL=$

Snnctrint the $\frac{?}{(R\frac{?}{?})}$ rhart

UCL $=as1$

$LCL=$

Compute the upper and lower control $limits$ for the $\stackrel{}{x}$ chart. $(Round$ your answers $to$ three decimal places.$)$

UCL $=1\mathrm{.}396$

$LCL=1$

$c$

What conclusions can $be$ made about the quality $of$ the process?

The $R$ chart indicates that the process variability $is$

$1vv$

$No$ samples fall

outside the $R$ chart control $limits.$ The $\stackrel{}{x}$ chart indicates that the process mean $is$ out $of$ control hat$()$

One sample falls

$x$ outside the $\stackrel{}{x}$ chart control $limits.$

$x$