The following are quality control data for a manufacturing process at Kensport Chemical Company. The date show the temperature in degrees centigrade at five points in time during a manufacturing cycle Sample R x 1 1 95.72 1.0 2 95.26 0.9 3 95.18 0.8 95.42 0.4 4 5 95.46 0.5 6 95.32 1.1 7 95.40 1.0 95.44 0.3 9 95.08 0.2 10 95.50 0.6 11 95.800.0 12 95.22 0.2 13 95.60 1.3 14 95.22 0.6 15 95.04 0. 16 95.72 1.1 17 94.82 0.5 18 95.46 0.5 19 95.60 0.4 20 95.74 0.6 The company is interested in using control charts to monitor the temperature of its manufacturing process. Compute the upper and lower controllimits for the chart. (Round your answers to three decimal places.) UCL - 90.788 X LC. - i Du X Construct the chart. UCL 2.00 1.75 1.50 1.25 1.00+ 0.75 0.50 0.25 0.00 2.00 1.75+ 1.50 1.25 1.00 2.0.75 0.50 0.25 + 0.00 2.00 1.75+ 1.50 1.25 1.00 0.75 0.50 2.00 1.75 1.50 1.25 1.00 0.75 0.30 0.25 0.00 M L.CL TOT 1.CL 0.00 2 4 6 8 10 12 14 16 18 20 Sample Number 2 4 6 8 10 12 14 16 18 20 Sample Number 1.CL 2 4 6 8 10 12 14 16 18 20 Sample Number 2 4 6 8 10 12 14 16 18 20 Sample Number Compute the upper and lower control limits for the x chart. (Round your answers to three decimal places.) UCL-1427 Jx X LOL - IX Construct the x chart. 96 25+ UCL UCI UCL 96.251 96.00+ $ 95.75 95.50 L 95.25 95.00 94.75 96.25 + 96.00+ 95,75 95.50 + 95.25 95.00 94.75 96.25 95.00 95.75 95.50 95.25 95.00 94.75 96.00 95.75 95.50 95.25 95.00 94.75 tea . V LCL LCL LCL LCL 2 4 6 8 10 12 14 16 18 20 Sample Number 2 4 6 8 10 12 14 16 18 20 Sample Number 2 4 6 8 10 12 14 16 18 20 Sample Number 2 4 6 8 10 12 14 16 18 20 Sample Number 0 og What conclusions can be made about the quality of the procesz? The chart indicates that the process variability is in control R No samples tal V outside the chart controllimits. The chart indicates that the process mean is out of control Two samples fall outside the chart controllimits. x