Question: The following helicopter has four rotor blades rotating at angular velocity 2 (rad/sec). It's flying forward at velocity Voo. The blade angle y is

The following helicopter has four rotor blades rotating at angular velocity 2 (rad/sec). It's flying forward at velocity Voo. The blade angle y is called the azimuth; it is zero degrees for a blade pointed aft (toward the tail) and increases counterclockwise. At a particular point in time (say at t=0), blade 1 is at y=0, blade 2 lags blade 1 by 90 deg (y-270 deg), etc. Say the blade radius is 28 ft and Q is 27 rad/sec. For forward flight at Vo 25 ft/s, at t=0 (the blades positioned as they are in the picture), compute the tangential velocity of the four blade tips (points 1-4). Treat each blade as having its own local coordinate system with origin at the blade tip, with axial direction positive out the tip of the blade and tangential direction positive toward the leading edge of the blade. Y=270 = Y= 0 F y Z X Y = 180 Y-90 Voo
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