The following LC-3 instructions execute starting from the point shown by the comment.

1 2 3 4 5 6 7 8 9 10 11 12 13

; start LC-3 execution here 0101 001 001 1 00000 0101 011 011 1 00000 0001 001 001 1 01100 0001 011 011 1 00101 1001 010 001 111111 1001 100 011 111111 0101 010 010 0 00 011 0101 100 100 0 00 001 1001 010 010 111111 1001 100 100 111111 0101 010 010 0 00 100 1001 010 010 111111 ; end LC-3 execution here

After the code reaches the end of the code (the last comment), what bits are held in R1? And in R2? And in R3? And in R4?

Lines 1-4 initialize the input registers, while lines 5-12 generate the output of the function, and store the result in register R2. What Boolean function is this code trying to implement? Specifically, identify the two input registers and the Boolean function implemented:

R2 R? (mystery Boolean function?) R?