Question: The function calc_sin() takes 1 parameters type double prints out the result of sin(theta) and does not return anything. However, the code produces the wrong

 The function calc_sin() takes 1 parameters type double prints out the

The function calc_sin() takes 1 parameters type double prints out the result of sin(theta) and does not return anything. However, the code produces the wrong output when executed as shown in the figure below. Rewrite the single line of code that will fix this bug. mainc 1 #include 2 #include 4 void calc_sin(double theta); 5. int main() { 3 6 7 8 9 10 11 double angle_rad = 12.34; calc-sin(angle_rad); return 0; 12 } 13 14- void calc_sin(double theta){ printf("sin(%.21f) = %.21f", theta, sin(theta)); 17 ] 15 16 18 stderr input Compilation failed due to following error(s). main.c: In function 'main': mainic:9:5: error: 'calc' undeclared (first use in this function) calc-sin(angle_rad); mains:9:5: note: cach undeclared identifier is reported only once for each function it appear

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