Question: The function magicbox () takes 3 parameters type of double returns the result of a+b-c. However, the code produces an error when executed as shown

 The function magicbox () takes 3 parameters type of double returns

the result of a+b-c. However, the code produces an error when executed

The function magicbox () takes 3 parameters type of double returns the result of a+b-c. However, the code produces an error when executed as shown in the figure below. Rewrite the single line of code that will fix this bug. main c 1 #include 2 #include 3 4 double magicbox(double a, double b, double c); 5- int main() { 6 7 8 double a = 1, b = 2, C = 3; 9 printf("The magicbox returns %lf", magicbox(a, b)); 10 11 return 0; 12} 13 14- double magicbox (double a, double b, double c){ 15 16 return a * b - C; 17 18 } 19 Compilation failed due to following error(s). main.c: In function 'main': 40 error too few arguments to function magicbox' printf("The magicbox returns %lf", magicbox(a, b)); Anwww main. 6:4:8: note: declared here double magicbox( double a, double b, double c); ANNNNNNN

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