Question: The function magicbox ( takes 3 parameters type of double returns the result of a*b-c. However, the code produces an error when executed as shown

 The function magicbox ( takes 3 parameters type of double returns

The function magicbox ( takes 3 parameters type of double returns the result of a*b-c. However, the code produces an error when executed as shown in the figure below. Rewrite the single line of code that will fix this bug. main.c 1 #include 2 #include 3 4 double magicbox (double a, double b, double c); 5. int main() { 6 7 8 double a = 1, b = 2, C = 3; 9 printf("The magicbox returns %1f", magicbox(a, b)); 10 11 return 0; 12} 13 14. double magicbox(double a, double b, double c){ 15 16 return a b - c; 17 18 ) 19 stderr input Compilation failed due to following error(s). main.c: In function 'main': main..:9:40: error: too few arguments to function 'magicbox' printf("The magicbox returns Xlf", magicbox(a, b)); main.c:4:8: note: declared here double magicbox(double a, double b, double c); MW AN

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