Question: The function h(x) = ex is the composition of the three functions f(x)=x, g(x)=e*, and k(x) = x. Therefore, h(x) = (fogok)(x) = f(g(k(x)))

The function h(x) = ex is the composition of the three functions f(x)=x, g(x)=e*, and k(x) = x. Therefore, h(x) = (fogok)(x) = f(g(k(x))) = e. (Equation 1) dh a) Find by taking the derivative of Equation 1 by using quick methods. dx b) Now, find the derivative by using the chain rule in Liebniz notation. Does this agree the derivative found in part (a)? Chain rule in Liebniz notation: k(x)=x Hint: g(k)= ek f(g)=g dh df dg dk dx dg dk dx
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