The integral in the equation can be evaluated analytically for simple nozzle shapes. l2 dl 20...

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The integral in the equation can be evaluated analytically for simple nozzle shapes. l2 dl 20 pv 14 d; 1 'n 2 (Sweet used the following approximation for the gauge pressure required in the reservoir of a continuous jetting system from Additive Manufacturing Technologies by lan Gibson, David Rosen) Ap = 32dv S Assume that the nozzle is conical with the entrance diameter of de and the exit diameter dx. (a) Evaluate the integral analytically. (this is the part that needs to be solved) + + Use your integrated expression to compute pressure drop through the nozzle, instead of (7.3), for the following variable variable values: following p [kg/m] 1000 1000 de [mm] dx [mm] (b) 0.04 0.02 (c) 0.04 0.02 (d) 0.04 (e) 0.1 (f) 0.1 0.02 0.04 0.04 1 [mm] @[cP] 0.1 1 0.1 40 1.0 1 5.0 1 5.0 40 1000 1000 1000 y [N/m] 0.072 0.072 0.072 0.072 0.025 v [m/s] 10 10 10 10 10 The integral in the equation can be evaluated analytically for simple nozzle shapes. l2 dl 20 pv 14 d; 1 'n 2 (Sweet used the following approximation for the gauge pressure required in the reservoir of a continuous jetting system from Additive Manufacturing Technologies by lan Gibson, David Rosen) Ap = 32dv S Assume that the nozzle is conical with the entrance diameter of de and the exit diameter dx. (a) Evaluate the integral analytically. (this is the part that needs to be solved) + + Use your integrated expression to compute pressure drop through the nozzle, instead of (7.3), for the following variable variable values: following p [kg/m] 1000 1000 de [mm] dx [mm] (b) 0.04 0.02 (c) 0.04 0.02 (d) 0.04 (e) 0.1 (f) 0.1 0.02 0.04 0.04 1 [mm] @[cP] 0.1 1 0.1 40 1.0 1 5.0 1 5.0 40 1000 1000 1000 y [N/m] 0.072 0.072 0.072 0.072 0.025 v [m/s] 10 10 10 10 10