The reaction: 2A + 2B --> D + F was studied carefully and the following mechanism...

  

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The reaction: 2A + 2B --> D + F was studied carefully and the following mechanism was finally Determined to be the following: A+ A--> C (slow) C+B --> D+E (fast) E + B --> (very fast) The rate law for the reaction would therefore be 1) rate = K[A]² 2) rate = K[A]²[B]² 3) rate = K[C][B] 4) rate= K[A][B]3 (5) rate = K[A][B] The reaction: 2A + 2B --> D + F was studied carefully and the following mechanism was finally Determined to be the following: A+ A--> C (slow) C+B --> D+E (fast) E + B --> (very fast) The rate law for the reaction would therefore be 1) rate = K[A]² 2) rate = K[A]²[B]² 3) rate = K[C][B] 4) rate= K[A][B]3 (5) rate = K[A][B]

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A A slow DE fast EB Verly fast The rate wil... View the full answer