This is C++ program. using for loop only please. Thank you.

Classify a number as Perfect, Deficient or Abundant. . Validate user input. This classification has meaning ONLY for POSITIVE integers. . You do NOT have to validate if the input is numeric Just let the program have a run time error or . if it is an integer just ignore the decimal part A number is PERFECT if the sum of each factors, NOT including the number itself is equal to the number. Example 6 1+2+3 A number is DEFICIENT if the sum of each factors, NOT including the number itself is less than the number. Example91+3. A number is ABUNDANT if the sum of each factors, NOT including the number itself is greater than the number. Example 12