Translate the following C code to LEGv8 assembly code. Use a minimum number of instructions. Assume that the values of a, b, i, and j are in registers X0, X1, X10, and X11 respectively. Also, assume that register 2x holds the base address of the array D.

for(i = 0; i < a; i++) {

for(j = 0; j < b; j++) {

D[4*j] = i + j;

}

}