Question: When there are coefficients in the reaction formula, how does that change the integrated rate law? For example I know that in a 2nd-order reaction

When there are coefficients in the reaction formula, how does that change the integrated rate law? For example I know that in a 2nd-order reaction of 2A->B, the integrated rate law becomes but what about when the coefficients are A->2B? What about reactions of other orders?

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