Write a function:

void solveQuadratic$($double a$,$ double b$,$ double c$,$ double& x$1,$ double& x$2)$

Use the quadratic formula to solve the quadratic equation given by ax$2+$ bx $+$ c $=0.$ You will have to do the math twice $-$ once for the version that says $-$b $+...$ and once for the version that says $-$b $-...$

Use x$1$ and x$2$ to communicate the answers. x$1$ should store the result to the $+$ version of the formula and x$2$ should store the $-$ version. If there is only one answer, both x$\text{'}$s will be the same. Do not worry about cases with no solution.

Code:

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#include

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#include

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using namespace std;

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$//$ Any changes above will be ignored

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$//$ YOUR$\_$CODE$\_$BELOW

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$$

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$//$ YOUR$\_$CODE$\_$ABOVE

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$//$ Any changes below will be ignored

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int main$()\{$

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$$double answer$1=0,$ answer$2=0$;

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$$double in$1,$ in$2,$ in$3$;

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$$cin $>>$ in$1>>$ in$2>>$ in$3$;

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$$solveQuadratic$($in$1,$ in$2,$ in$3,$ answer$1,$ answer$2)$;

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$$

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$//$ If answer$1$ and $2$ are still $0,$ your function did not modify them

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$$cout $<<$ answer$1<<","<<$ answer$2<<$ endl;

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$\}$