Question: x 2_ X-3x te-2=0 + 0 Interval [-1, 2 using Fixed Point Method Stop: Xit - XK ), 0 0 05 = L x x

x 2_ X-3x te-2=0 + 0 Interval [-1, 2 using Fixed

x 2_ X-3x te-2=0 + 0 Interval [-1, 2 using Fixed Point Method Stop: Xit - XK ), 0 0 05 = L x x 16.000

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