Question: Derive (15-44) and use it to solve the following problem. Sulfate ion is to be removed from 60 L of water by exchanging it with

Derive (15-44) and use it to solve the following problem. Sulfate ion is to be removed from 60 L of water by exchanging it with chloride ion on 1 L of a strong-base resin with relative molar selectivities as listed in Table 15.6 and an ion-exchange capacity of 1.2 eq/L of resin. The water to be treated has a sulfate-ion concentration of 0.018 eq/L and a chloride-ion concentration of 0.002 eq/L. Following the attainment of equilibrium ion exchange, the treated water will be removed and the resin will be regenerated with 30 L of 10 wt% aqueous NaCl. 

(a) Write the ion-exchange reaction. 

(b) Determine the value of KSO2-; Cl-

(c) Calculate equilibrium concentrations cSO2-, cCI, qSO2-4, and qCI- in eq/L for the initial ionexchange step. 

(d) Calculate the concentration of Clin eq/L for the regenerating solution. 

(e) Calculate cSO2-, and qClupon reaching equilibrium in the regeneration step. 

(f) Are the separations sufficiently selective?

Step by Step Solution

3.49 Rating (162 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a The ionexchange reaction is Resin SO24 Cl b The value of KSO24 Cl can be calculated using the foll... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Separation Process Principles Chemical Questions!