Consider the circuit shown in Figure P11.2. Assume \(g_{m}=1.0 \mathrm{~mA} / \mathrm{V}\). Assume the input signal voltages are \(v_{1}=0.7+0.1 \sin \omega t \mathrm{~V}\) and \(v_{2}=\) \(0.7-0.1 \sin \omega t \mathrm{~V}\).

(a) Determine the signal voltages (i) \(v_{o 1}\), (ii) \(v_{o 2}\), and (iii) \(v_{o 1}-v_{o 2}\).

(b) Using the results of part (a), determine the small-signal voltage gains (i) \(A_{d 1}=\Delta v_{o 1} / \Delta\left(v_{1}-v_{2}\right)\), (ii) \(A_{d 2}=\Delta v_{o 2} / \Delta\left(v_{1}-v_{2}\right)\), and (iii) \(A_{d 3}=\Delta\left(v_{o 1}-v_{o 2}\right) / \Delta\left(v_{1}-v_{2}\right)\).

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V+= 5 V R= 5 102 Figure P11.2 8m2 R= 15