Question: For a power MOSFET, (theta_{text {dev-case }}=1.5^{circ} mathrm{C} / mathrm{W}, theta_{text {snk-amb }}=2.8^{circ} mathrm{C} / mathrm{W}), and (theta_{text {case }-mathrm{snk}}=0.6^{circ} mathrm{C} / mathrm{W}). The ambient

For a power MOSFET, \(\theta_{\text {dev-case }}=1.5^{\circ} \mathrm{C} / \mathrm{W}, \theta_{\text {snk-amb }}=2.8^{\circ} \mathrm{C} / \mathrm{W}\), and \(\theta_{\text {case }-\mathrm{snk}}=0.6^{\circ} \mathrm{C} / \mathrm{W}\). The ambient temperature is \(25^{\circ} \mathrm{C}\).

(a) If the maximum junction temperature is limited to \(T_{j, \max }=120^{\circ} \mathrm{C}\), determine the maximum allowed power dissipation.

(b) Using the results of part (a), determine the temperature of the case and heat sink.

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