A CT with an excitation curve given in Figure 10.39 has a rated current ratio of 500:5

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A CT with an excitation curve given in Figure 10.39 has a rated current ratio of 500:5 A and a secondary leakage impedance of \(0.1+j 0.5 \Omega\). Calculate the CT secondary output current and the CT error for the following cases:

(a) The impedance of the terminating device is \(4.9+j 0.5 \Omega\) and the primary CT load current is \(400 \mathrm{~A}\).

(b) The impedance of the terminating device is \(4.9+j 0.5 \Omega\) and the primary CT fault current is \(1200 \mathrm{~A}\).

(c) The impedance of the terminating device is \(14.9+j 1.5 \Omega\) and the primary CT load current is \(400 \mathrm{~A}\).

(d) The impedance of the terminating device is \(14.9+j 1.5 \Omega\) and the primary CT fault current is \(1200 \mathrm{~A}\).

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Power System Analysis And Design

ISBN: 9781305632134

6th Edition

Authors: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

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