The distance from the center of the breastbone to a man's hand, with the arm outstretched and

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The distance from the center of the breastbone to a man's hand, with the arm outstretched and horizontal to the floor, is 1.0 m. The man is holding a 10.0-kg dumbbell, oriented vertically, in his hand, with the arm horizontal. What is the torque due to this weight about a horizontal axis through the breastbone perpendicular to his chest?
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Physics

ISBN: 978-0077339685

2nd edition

Authors: Alan Giambattista, Betty Richardson, Robert Richardson

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