Question: The energy needed for the following process is 1.96 104 kJ/mol: Li(g) Li3+(g) + 3e- If the first ionization energy of lithium is

The energy needed for the following process is 1.96 × 104 kJ/mol:
Li(g) → Li3+(g) + 3e-
If the first ionization energy of lithium is 520 kJ/mol, calculate the second ionization energy of lithium, that is, the energy required for the process
Li+(g) → Li2+(g) + e-

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