Question: The Nernst equation can be applied to half reactions. Calculate the reduction potential at 25oC of each of the following half cells. a. Cu/ Cu2+
The Nernst equation can be applied to half reactions. Calculate the reduction potential at 25oC of each of the following half cells.
a. Cu/ Cu2+ (0.10 M) (The half reaction is Cu2+ + 2e– n Cu.)
b. Cu/ Cu2+ (2.0 M)
c. Cu/ Cu2+(1.0 × 10–4 M)
d. MnO4– (0.10 M)/ Mn2+ (0.010 M) at pH = 3.00 (The half reaction is MnO4- + 8H+ + 5e– n Mn2+ + 4H2O.)
e. MnO4 2 (0.10 M)/ Mn2+ (0.010 M) at pH = 1.00
a. Cu/ Cu2+ (0.10 M) (The half reaction is Cu2+ + 2e– n Cu.)
b. Cu/ Cu2+ (2.0 M)
c. Cu/ Cu2+(1.0 × 10–4 M)
d. MnO4– (0.10 M)/ Mn2+ (0.010 M) at pH = 3.00 (The half reaction is MnO4- + 8H+ + 5e– n Mn2+ + 4H2O.)
e. MnO4 2 (0.10 M)/ Mn2+ (0.010 M) at pH = 1.00
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