The production of 1,3-butadiene can be carried out by the dehydrogenation of 1- butene: C2H5CH:CH2(g) CH2:CHCH:CH2(g)
Question:
C2H5CH:CH2(g) → CH2:CHCH:CH2(g) + H2(g)
Side reactions are suppressed by the introduction of steam. If equilibrium is attained at 950 K and 1 bar and if the reactor product contains 10-mol-% 1,3-butadiene, find:
(a) The mole fractions of the other species in the product gas.
(b) The mole fraction of steam required in the feed.
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Number the species as shown Basis is 1 mol species 1 x mol steam n 0 1 x ...View the full answer
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Related Book For 
Introduction to Chemical Engineering Thermodynamics
ISBN: 978-0071247085
7th edition
Authors: J. M. Smith, H. C. Van Ness, M. M. Abbott
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