When 2-bromo-2-methylbutane is heated in a mixture of ethanol and water, it gives a 64% yield of

Question:

When 2-bromo-2-methylbutane is heated in a mixture of ethanol and water, it gives a 64% yield of substitution products and a 36% yield of elimination products.

(a) What mechanisms does this reaction follow?

(b) Show the structures of the substitution products?

(d) Under the same reaction conditions, how would 2-iodo-2-methylbutane differ from the bromide in its rate of reaction in the products of its reaction?