Question: An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2 at2 + v0t + s0

An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2 at2 + v0t + s0 for the object.
1. At t = 1 second, s = 128 feet
At t = 2 seconds, s = 80 feet
At t = 3 seconds, s = 0 feet
2. At t = 1 second, s = 132 feet
At t = 2 seconds, s = 100 feet
At t = 3 seconds, s = 36 feet

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1 s 12at 2 v 0 t s 0 1 128 2 80 3 0 128 12a v 0 s 0 a 2v 0 2s 0 256 80 2a 2v 0 s 0 2a 2v 0 s 0 ... View full answer

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