Exercise 2.7 explored simple register renaming: when the hardware register renamer sees a source register, it substitutes the destination T register of the last instruction to have targeted that source register. When the rename table sees a destination register, it substitutes the next available T for it. But superscalar designs need to handle multiple instructions per clock cycle at every stage in the machine, including the register renaming. A simple scalar processor would therefore look up both src register mappings for each instruction, and allocate a new destination mapping per clock cycle. Superscalar processors must be able to do that as well, but they must also ensure that any dest-to-src relationships between the two concurrent instructions are handled correctly. Consider the sample code sequence in Figure 2.38. Assume that we would like to simultaneously rename the first two instructions. Further assume that the next two available T registers to be used are known at the beginning of the clock cycle in which these two instructions are being renamed. Conceptually, what we want is for the first instruction to do its rename table lookups, and then update the table per its destination's T register. Then the second instruction would do exactly the same thing, and any interinstruction dependency would thereby be handled correctly. But there's not enough time to write that T register designation into the renaming table and then look it up again for the second instruction, all in the same clock cycle. That register substitution must instead be done live (in parallel with the register rename table update). Figure 2.39 shows a circuit diagram, using multiplexers and comparators, that will accomplish the necessary on-the-fly register renaming. Your task is to show the cycle-by-cycle state of the rename table for every instruction of the code. Assume the table starts out with every entry equal to its index (T0 = 0; T1 = 1, . . .)?