Question: For the geared system discussed in Problem 3.23, shown in Figure, the inertias are given in kg-m2 as I1 = 10-3 I2 = 3.84 x
I1 = 10-3
I2 = 3.84 x 10-3
I3 = 0.0148
I4 = 0.03
I5 = 0.15
The speed ratios are
Ï1/ Ï2 = Ï2/ Ï3 = 1.6
Derive the system model in terms of the speed Ï3, with the applied torque T as the input. The shaft inertias are negligible.
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The total kinetic energy is KE 12 I 4 I 1 w 2 1 12 I 2 w 2 2 12 I 3 I 5 w 2 3 Substit... View full answer
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