Question: Let n,k Z+, and define p(n, k) to be the number of partitions of n into exactly k (positive-integer) summands. Prove that p(n, k)
Let n,k ∈ Z+, and define p(n, k) to be the number of partitions of n into exactly k (positive-integer) summands. Prove that p(n, k) = p(n - 1), (k - 1) + p(n - k, k).
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There are two cases to consider Case 1 1 is a summand Here there are pn 1 k ... View full answer
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