Question: Let X nj , j = 1, ..., k n be row-wise independent r.v.s with ÉX nj = 0, and Then with and under the
![]()
and
![]()
Then with
![]()
and under the assumption that L(Sn) N(0, 1), show that
![]()
By Theorem 1, it follows that, for every É > 0,
![]()
n where Fnj is the d.f. of Xnj. One way of proceeding is to show that
![]()
![]()
![]()
o?(Xnj) = o < o, s, = E1 = 1,
Step by Step Solution
3.48 Rating (171 Votes )
There are 3 Steps involved in it
We assume that S n d N0 1 and we shall show that n j 1 X 2 nj P n 1 Si... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
742-M-S-P (6990).docx
120 KBs Word File
