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systems analysis and design
The Analysis And Design Of Linear Circuits 8th Edition Roland E. Thomas, Albert J. Rosa, Gregory J. Toussaint - Solutions
6–17 For t ≥ 0 the current through a 100-mH inductor is iLðtÞ = 100 t e−1000t A. Derive an expression for vLðtÞ. Is the inductor absorbing power or delivering power or both?
6–16 For t ≥ 0 the voltage across a 100-mH inductor is vLðtÞ = 500 t uðtÞ V. At t = 2ms the inductor current is observed to be zero. Find the value of iL(0).
6–15 A voltage vLðtÞ = 5 cosð1000 ntÞ V appears across a 50-mH inductor, where n is a positive integer that controls the frequency of the input signal. The amplitude of the input signal is constant. Assume iLð0Þ = 0A. Use MATLAB and symbolic variables to compute an expression for iLðtÞ.On
6–14 Repeat Problem 6–13 when the voltage across a 20-mH inductor is vLðtÞ = 40 e−2000t V. Plot iLðtÞ versus time when iLð0Þ = – 1A.
6–13 For t ≥ 0 the voltage across a 100-mH inductor is vLðtÞ = 15 e−100t V. Plot iLðtÞ versus time when iLð0Þ = 0A.(a) Solve using Multisim. In Multisim use the exponential voltage source, and set its initial value to 15 V and the pulsed value to 0 V. Set the rise-time appropriately.
6–12 For t ≥ 0 the current through a 4300-μH inductor is iLðtÞ = 1 e– 10,000t A. Find vLðtÞ, pLðtÞ, and wLðtÞ for t ≥ 0.Is the inductor absorbing power, delivering power, or both?
6–10 A 100-μF capacitor has no voltage across it at t = 0:A current flowing through the capacitor is given as iCðtÞ = 2 uðtÞ – 3uðt – 3Þ + uðt – 6ÞmA. Find the voltage across the capacitor at t = 4 s. Repeat for t = 6s.
6–9 For t ≥ 0 the current through a 0:33-μF capacitor is iCðtÞ = 5 sinð1000πtÞmA. Using Multisim, plot vCðtÞ versus time when vCð0Þ = −5 V. In Multisim, use the ac current source—note that the frequency is in Hz—and set the other parameters appropriately. Click on the capacitor
6–5 For t ≥ 0 the current through capacitor is iCðtÞ = 10 t uðtÞmA.At t = 0 the capacitor voltage is 3 V. At t = 1ms the voltage is 8 V. Find the capacitance of the device.
6–4 The current through a 0:1-μF capacitor is a rectangular pulse with an amplitude of 2mA and a duration of 5 ms. Find the capacitor voltage at the end of the pulse when the capacitor voltage at the beginning of the pulse is –1V.
6–3 The voltage across a 2200-pF capacitor is vCðtÞ = 50 cos(2π104t )V. Derive expressions for iCðtÞ and pCðtÞ. Is the capacitor absorbing power, delivering power, or both?
6–2 For t ≥ 0 the voltage across a 0:022-μF capacitor is vCðtÞ = 5 e−100t uðtÞ V. Derive expressions for iCðtÞ and pCðtÞ. Is the capacitor absorbing power, delivering power, or both?
6–1 For t ≥ 0 the voltage across a 1-μF capacitor is vCðtÞ = 10 uðtÞ V. Derive expressions for iCðtÞ and pCðtÞ. Is the capacitor absorbing power, delivering power, or both?
The current through a series connection of two 1-μF capacitors is a rectangular pulse with an amplitude of 2 mA and a duration of 10 ms. At t = 0 the voltage across the first capacitor is+10 V and across the second is zero.(a) What is the voltage across the series combination at t = 10 ms?(b) What
(a) A 150-μH inductor is in parallel with two other identical inductors. That combination is in series with a 100-μH inductor. What is the equivalent inductance of the connection?(b) A capacitor bank consists of five hundred 400-VDC, 10-mF capacitors in parallel. How much energy can the bank
The input to the circuit in Figure 6–19 is υSðtÞ = 10 e−5t u t ð Þ V:(a) For υCð0Þ = 0, derive an expression for the output voltage, assuming the OP AMP is in its linear range.(b) Does the OP AMP saturate with the given input?
The current through a 2.5-mH inductor is a damped sine iðtÞ = 10e−500t sin 2000t. Plot the waveforms of the element current, voltage, power, and energy.
For t < 0, the current through a 100-mH inductor is zero. For t ≥ 0, the current is iLðtÞ = 20e−2000t −20e−4000t mA.(a) Derive an expression for the voltage across the inductor for t >0.(b) Find the time t > 0 at which the inductor voltage passes through zero.(c) Derive an expression for
For t > 0, the voltage across a 4-mH inductor is υLðtÞ = 20e−2000t V. The initial current is iL(0) = 0.(a) What is the current through the inductor for t >0?(b) What is the power for t >0?(c) What is the energy for t >0?
Find the power and energy for the capacitor in Exercise 6–3.
Find the power and energy for the capacitors in Exercise 6 – 2.
For t ≥ 0 the voltage across a 200-pF capacitor is 5e−4000t V.(a) What is the charge on the capacitor at t = 0 and t= + ∞?(b) Derive an expression for the current through the capacitor for t ≥ 0.(c) For t > 0 is the device absorbing or delivering power?
(a) The voltage across a 10-μF capacitor is 25½sin 2000tuðtÞV. Derive an expression for the current through the capacitor.(b) At t = 0 the voltage across a 100-pF capacitor is −5 V. The current through the capacitor is 10 u t ð Þ−u t−10−4 μA. What is the voltage across the
6-3 Equivalent Inductance and Capacitance (Sect. 6–4)(a) Derive equivalence properties of inductors and capacitors or use equivalence properties to simplify LC circuits.(b) Given an RLC circuit with dc inputs, find the dc currents and voltage responses.
6-2 Dynamic OP AMP Circuits (Sect. 6–3)(a) Given an OP AMP integrator or differentiator, determine the output for specified inputs.(b) Given an RC circuit containing OP AMPs, find the input–output relationship and construct a block diagram.(c) Design an RC circuit containing OP AMPs that
6-1 Capacitor and Inductor Responses (Sects. 6–1, 6–2)(a) Given the current through a capacitor or an inductor, find the voltage across the element.(b) Given the voltage across a capacitor or an inductor, find the current through the element.(c) Find the power and energy associated with a
Determine the current, voltage, and power delivered to the 500-Ω output load in Figure 4–4. Then find the power gain defined as pO=pS. 25 A w iy io + 48ix Vo 502 is 300 500 Source or input circuit FIGURE 4-4 Load or output circuit
Find the output vO in terms of the input vS in the circuit in Figure 4–5.Then if RS =RP = 100 Ω, RC =RL =1 kΩ, and r =1 kΩ, find the gain K = vO=vS for the circuit VS 1+ FIGURE 4-5 Rs ix Rc w Rp www + www +1 rix RL Vo
Use the graph in Figure 4–6(c) to select a value of RF so that the gain is −25;000 and repeat for −40;000 Gain (K) 0.0 -5.0k -10.0k -15.0k -20.0k -25.0k -30.0k -35.0k -40.0k Device parameter sweep (1.63 k2, K=-200) (6.7 MS2, K=-20,000) -45.0k -50.0k 158 1k 10k 100k IM 10M 63M Feedback
With all other resistors set to 1 kΩ and μ=105, select an appropriate value for RF in Figure 4–6(a) so that the gain jKj can never be larger than 10,000, or smaller than 50. VS Rs RF Rc VD VC VA w w is +1 + 1; RL w + Vo - Load or output circuit (a) Source or input circuit VCVS FIGURE 4-6 (a)
For the circuit of Figure 4–7, use node-voltage analysis to find expressions for the unknown node voltages. Write your results as a matrix in Ax = b form. R VA www VB. VC Rp VD w www R (+1 VSI +VS2 ww RB RE Vo BiB E) FIGURE 4-7 Reference
For the circuit in Figure 4–7, use the node-voltage equations in Eqs. (4–7) to find the output voltage υO when R1 =1 kΩ, R2 =3 kΩ, RB = 100 kΩ, RP =1:3 kΩ, RE =3:3 kΩ, and β = 50. R VA www VC Rp vp VB w www (+1 VSI VS2 R RE Vo RB BiB E FIGURE 4-7 Reference
For the circuit in Figure 4–8 find the voltage gain Kv = υO=υS, and the current gain Ki = iO=iS using node-voltage analysis. VS VA RF www + Vx- VB + . RL +21 w FIGURE 4-8 Reference
(a) Formulate node-voltage equations for the circuit in Figure 4–9.(b) Solve the node-voltage equations for υO and iO in terms of iS. is VA 2 KQ VB + 500 500 io Vo
Determine the output voltage of the circuit shown in Figure 4–10(a) using Multisim 0.1 V 50 w 100 + (a) + 22 w + 33 100 vx
Find iO using Multisim for the circuit of Figure 4–11(a). 10 V ( + 100 ww (a) 90ix io 500
The circuit in Figure 4–12(a) is a model of an inverting OP AMP circuit.(a) Use node-voltage analysis to find the output υO in terms of the input υS.(b) Evaluate the input-output relationship found in part (a) as the gain μ becomes very large.(c) Assume R1 =R2 = 100 Ω, μ = 1000, and R4 =1
Use node-voltage analysis to find υO for the circuit in Figure 4–13. R ww +1- Vx R R ww + VS RL vo (+1) FIGURE 4-13
(a) Formulate mesh-current equations for the circuit in Figure 4–14.(b) Use the mesh equations to find υO and RIN when R1 =50 Ω, R2 =1 kΩ, R3 = 100 Ω, R4 =5 kΩ, and g = 100 mS. RIN Source transformation R R io R R ww ww ww ww +Vx- +x- R3 gvx VS R3 R4 vo VS iA iB R4 gR3Vx Given circuit (a)
Write a set of node-voltage equations and use them to find υO and RIN for the circuit in Figure 4–14. Use the parameter values given in Example 4–6. RIN Source transformation R R io R R2 ww ww ww ww +Vx- R3 gvx VS R3 R4 vo VS iA iB RA gR3Vx Given circuit (a) RIN Modified circuit (b) FIGURE 4-14
The circuit in Figure 4–15 is a model of a bipolar junction transistor operating in the active mode. Use mesh analysis to find the transistor base current iB. Excluded Vcc +1 Rc C BiB ww ic i2 + B ww RB FIGURE 4-15 iB E ww RE Supermesh
Use mesh analysis to find the current iO in Figure 4–16 when the element E is a dependent current source 2ix with the reference arrow directed down. 10 V 4 www 10 E FIGURE 4-16
Use mesh analysis to find the current iO in Figure 4–16 when the element E is a dependent voltage source 2000ix with the plus reference at the top. 10 V 4 ww FIGURE 4-16 10 E
The circuit in Figure 4–17(a) represents a small-signalmodel of a field effect transistor(FET) amplifier with two inputs, υS1 and υS2. Use Multisim to solve for the inputoutput relationship of the circuit. (Hint: Use superposition to find the respective gains due to the two sources, for
It is very important in designing differential amplifiers that the two transistors be matched in every way so that the outputs are balanced. Use Multisim to determine the relationship in the circuit of Figure 4–17(a) if the transconductance of FET G2 is 2.9 mS rather than 3 mS + VSI gvx R (3) rds
Find the input resistance of the circuit in Figure 4–18. is VIN (A) RE BIIN Vo + RIN FIGURE 4-18 RL
Your task is to design a transistor gain stage with a voltage gain (K) of −150. The transistor you have has a β of 90. Use the circuit in Figure 4–18 and select appropriate values for RL and RE. Start by first finding the voltage gain K = vO=vIN. IN A) isVIN RE RIN FIGURE 4-18 BiIN Vo + RL
Find the Thévenin equivalent at the output interface of the circuit in Figure 4–19 (A) +1 VS Ro B +- Load FIGURE 4-19 RT, VT
Find the input resistance and output Thévenin equivalent of the circuit in Figure 4–20. +1 RF ww + VF- VS RIN +1. FIGURE 4-20 Ro VL RL VT. RT
The known parameters in Figure 4–25 are β = 100, Vγ =0:7V, RC =1 kΩ, and VCC = 5 V. The circuit is to function as a digital inverter that meets two conditions:1. An input of υS = 0 V must produce an output of υCE =5V.2. An input of υS = 5 V must produce an output of υCE =0V Select a value
Design an amplifier with a gain of K = 10.
Design a noninverting amplifier circuit with a gain of 710% using standard 10% resistors.(See inside back cover for standard values.)
The noninverting amplifier circuit in Figure 4–32(a) is operating with R1 =2R2 and VCC = 12 V. Over what range of input voltages υS is the OP AMP in the linear mode?
There is a need for anOPAMPnoninverting amplifier with a gain of 0:5. Design such a circuit.
Find the input-output relationship, that is, the K of the circuit in 4–35(a). +1 R w R P Vp IN VNO- ww Vo R3 RL R4 Source Voltage divider Passive circuit Noninverting amplifier Load Active circuit (a) VS Vp Vo KVD KAMP (b) FIGURE 4-35
(a) Find υO in Figure 4–35(a) when R1 =R2 =1 kΩ, υS =1V, R3 =R4 =1 kΩ and RL = 100 Ω.(b) Repeat when R3 is a short circuit and the other values are the same. +1 R w Vp R P IN VNO- ww Vo R3 RL R4 Source Voltage divider Passive circuit Noninverting amplifier Load Active circuit (a) Vo Vp VS
There is a need for an OP AMP noninverting amplifier with a gain of 0:5. Design such a circuit. Use the results of Example 4–13 as a guide.
Digital (or even analog) Multimeters (DMMs) are ubiquitous engineering tools.They can be purchased for as little as $5 to as much as several thousand dollars. Most popular models are in the range of $100 to $200 and are hand-held portables. Clearly there must be differences to warrant such a wide
A DMM with a known internal resistance of 12:5MΩ is used to measure voltages across several resistors in the circuit shown in Figure 4–38. What voltage will be measured on the DMM across each resistor? 50 V (+ FIGURE 4-38 +VI- w 50 500 ww - V3 + 10
The circuits in Figure 4–36 have υS =1:5V, RS =2 kΩ, and RL =1 kΩ. Compute the maximum power available from the source. Compute the power absorbed by the load resistor in the direct connection in Figure 4–36(b) and in the voltage follower circuit in Figure 4–36(a). Discuss any differences.
The switch in Figure 4–40 moves from A to B. What is the output voltage υO when the switch is in position A and in position B? IV 10 330 Who B 100 A + Vo FIGURE 4-40 Voc = 15 V
A 2-mV signal υS needs to be amplified by a gain of −45010% using standard 10%resistors from the inside back cover. Design an appropriate circuit to amplify the signal.
Find the input-output relationship of the circuit in Figure 4–41(a). R B R3 R4 Vo ww w w VS R @ ww R4 Vo w ww ww RT R3 VT T REQ w (b) O RL www R4 vo ww RL www RL
Find the voltage gain K = vO=vS for the circuit in Figure 4–42. 68 vo 10 www 15 150 www ww 33 w + VS +1 www 15 FIGURE 4-42 +
In Figure 4–43, υ1 =0:6V, υ2 =0:4V, R1 =3:3 kΩ, R2 =4:7 kΩ, and RF =15 kΩ. Find υO. FIGURE 4-43 The inverting summer. R RF iF ww w Vo iN ww V +VI R VN K Vp Vo V2. K (b) (a)
Design an inverting summer that implements the input-output relationshipυO = −(5υ1 + 13υ2)
(a) Find υO in Figure 4–44(a) when υ1 = 2 V and υ2 = −0:5V.(b) If υ1 = 400mV and VCC = 15 V, what is the maximum value of υ2 for linear mode operation?(c) If υ1 = 500 mV and VCC = 15 V, what is the minimum value of υ2 for linear mode operation? 13 Vow 65 w vo V2W 5 +
Inverting amplifiers of the type discussed above have the ability to be easily designed with outputs being the weighted sum of the various inputs. While this type of OP AMP Summer is the most common by far, there is occasionally the need for a noninverting summer. In this example we analyze a
Design a noninverting summer for four inputs with equal gains of 50.
(a) Findthe input-output relationship of the subtractor circuit inFigure4–47.(b) If υCC = 15 V and υ1 = 3 V, what is the allowable range of υ2 for linear operation of the OP AMP? +1 10 w 10 w FIGURE 4-47 40 w + Vo - 15 +
Derive an expression for υO in Figure 4–49(a) in terms of the two inputs. Draw a block diagram representative of the circuit. +- 20 5 10 VA 5 V W 10 + (a) + + vo WWI 20 k21 10 .
Derive an expression for υO in Figure 4–50 in terms of the inputs υ1 and υ2. V 10 w 40 w 20 w 10 W V2 40 ww + vo
Derive an expression for υO in Figure 4–51 in terms of the two inputs υ1 and υ2. R R R3 R4 VA ww ww w w + Vo VI + + FIGURE 4-51 5 +1 +
We have looked at two ways to design subtractor circuits—the more common way as shown in Figure 4–46 and the less common way as shown in Figure 4–51. Your task is to design OP AMP circuits that meet the following expression: vO = −20v1 +10v2 using both realizations.At least one resistor in
Derive an expression for υO in Figure 4–53 in terms of the inputs υ1 and υ2. A +1 F (D) V +1 R B ww vo R R3 E FIGURE 4-53 +
Select values of R1, R2, and R3 in Figure 4–53 so that υO = 50(υ2 −υ1). A V2 +1 R B vo R3. E F R2 ww Vi +1 + FIGURE 4-53
In a particular application, it is necessary to implement the block diagram shown in Figure 4–54. The maximum individual OP AMP gain cannot exceed 2000. The input resistance of the first signal stage must be at least 10 kΩ. The nominal input signal υ1 is 1 μV.Two vendors have provided
Verify the solutions found in Evaluation Example 4–21 using Multisim.
Design the interface circuit in Figure 4–57 so that 200mW is delivered to the 500-Ω load. + 5V 50 w Interface circuit 500 ww ww + R3 R4 VI R R Circuit 1 Circuit 2 15 IV
Using the circuits and analyses shown in Design Example 4–22, how much power is being provided by the signal source in each design? What is providing the power to the load?
Design a circuit using OP AMPs that implements the input-output relationship 00-501 +402-203
A requirement exists for a circuit that implements the block diagram in Figure 4–59(a). The circuit in Figure 4–59(b) is a proposed solution.Abreadboard prototype of this circuit failed to pass preliminary testing. Why? 5 V FIGURE 4-59 -10- Vi 10 -20 (a) Block diagram w 1 10 10 ww 20 ww 100
The R-2R ladder DAC in Figure 4–62 has RF =40 kΩ, R=10 kΩ, and VREF = −3 V. Find the full-scale output and resolution of the converter. VREF A 2R isc VI W R 2R V2 w ---b R ww www ---b3 VA ---b4 2R ww 2R ww R 2R RF www + + vo
A student chooses to design a 6-bit weighted sum DAC for a project. The requirement is to have errors of 1% or less. What tolerance (accuracy) must the resistors used in the design have to meet the requirement?
A commercially available temperature transducer has the characteristics shown in Figure 4–67. Design an OP AMP circuit to interface the transducer output for temperatures ranging from −20C to 120C with a panel meter whose full-scale input range is 0 to 3 V. Use a standard 1:5-V battery as the
A pressure transducer must be connected to a boiler. The selected transducer is linear between 100 and 1000 psi. Specifically, it has the following characteristics: At 100 psi it produces 10 μV, and at 1000 psi it produces 100 μV. The output needs to be connected to a 0 – 10-V meter so that 100
A particular photoresistor varies from 10MΩ in total darkness to 10 kΩ in bright light. Design an interface system that will produce 5 V when the photoresistor senses bright light and 0 V when it is in total darkness. Show that the design works using Multisim.
Use a subtractor to design the interface for the example above.
A 2-kΩ potentiometer is connected to the flaps of an unmanned aerial vehicle, or UAV, to detect their position. When the flaps are at their maximum upward extension of +45, the potentiometer is at its maximum resistance of 2 kΩ; when the flaps are flat or 0, the potentiometer is set at 1 kΩ;
A strain gauge is a resistive device that measures the elongation (strain) of a solid material caused by applied forces (stress). A typical strain gauge consists of a thin film of conducting material deposited on an insulating substrate. When the gauge is bonded to a member under stress, its
Using the circuit shown in Figure 4–76, simulate the effect in Multisim varying the strain gauge RG2 from 120 Ω to 120:1 Ω in increments of 0:001 Ω. Plot the resulting output versus percent of stress (ΔL=L). RGI + +VREF=25 V VTR RA RA RB RG1 RG2 = 120 2 = = RG2+AR RB 0-5 mV 10 w 10 w 10
Instrumentation amplifiers are used as we have seen to provide signal processing of gain and bias to transducer outputs in preparation for use in ADC and other output devices. A well-designed instrumentation amplifier provides very high gain, very high common-mode rejection ratio, and very high
Design an instrumentation amplifier using the configuration of Figure 4–78 that has a gain of 105. Let RTR = 100 Ω. Note that no single stage can have a gain greater than 104. Verify your solution using Multisim. RTR VTR w R R KR Stage 1 Stage 2 KR M vo FIGURE 4-78
A commercial oven that heats a critical product cannot exceed a predetermined temperature.A temperature sensing thermocouple circuit produces a voltage proportional to the oven temperature. The output voltage varies linearly from 0 V at 0C to 12 Vat 1000C. Design a circuit that will detect when a
Find the comparator output voltage in Figure 4–82 for the following:(a) υ1 =2V, υ2 =3V, VCC =5V(b) υ1 =0V, υ2 = −3V, VCC =10V(c) υ1 = −2V, υ2 = −3V, VCC =3V V +1 FIGURE 4-82 +Voc 18+
The reference voltage in Figure 4–86(a) is VREF = 15 V. What are the output codes corresponding to υS = 1, 2, 5, 10, and 14 V? VREF vs(f) R ww w R R R 0.8VREF 0.6VREF w R b b b3 0.4VREF w 0.2VREF (a) b4
4–1 Find the voltage gain vO=vS and current gain iO=ix in Figure P4–1 for r = 10kΩ. 1+1 100 www 500 io w + 400 www FIGURE P4-1 +1 rix 2 kovo
4–2 Find the voltage gain vO=v1 and the current gain iO=iS in Figure P4–2. For iS = 10 mA, find the power supplied by the input current source and the power delivered to the 1:5-kΩ load resistor. ww + 100 90i is ( Vi 100 2 FIGURE P4-2 + io vo 1.5
4–3 Find the voltage gain vO=vS and current gain iO=ix in Figure P4–3 for g = 3 × 10−3 S. For vS = 10 V, find the power supplied by the input voltage source and the power delivered to the 2-kΩ load resistor 1 VS + 3 kvxgvx - FIGURE P4-3 io 500 ww +
4–4 (a) Find the voltage gain vO=vS and current gain iO=ix in Figure P4–4.(b) Validate your answers by simulating the circuit in Multisim +1 3.3 ww io 4.7 ww + 100ix 10 kn vo FIGURE P4-4
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