Question: (Delta) denotes the Laplace operator defined by Prove the identity [ operatorname{curl}(operatorname{curl}(mathbf{F}))=abla(operatorname{div}(mathbf{F}))-Delta mathbf{F} ] where (Delta mathbf{F}) denotes (leftlangleDelta F_{1}, Delta F_{2}, Delta F_{3}ightangle). 0x2
\(\Delta\) denotes the Laplace operator defined by

Prove the identity
\[
\operatorname{curl}(\operatorname{curl}(\mathbf{F}))=abla(\operatorname{div}(\mathbf{F}))-\Delta \mathbf{F}
\]
where \(\Delta \mathbf{F}\) denotes \(\left\langle\Delta F_{1}, \Delta F_{2}, \Delta F_{3}ightangle\).
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The identity you provided is a wellknown vector calculus identity involving the curl of the curl of a vector field mathbfF This identity is given by a... View full answer
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