Question: Recall that the substitution x = a sec implies either x a (in which case 0 < /2 and tan

Recall that the substitution x = a sec θ implies either x ≥ a (in which case 0 ≤ θ < π/2 and tan θ ≥ 0) or x ≤ -a (in which case π/2 < θ ≤ π and tan θ ≤ 0).

Graph the functionVx? – 9 f(x) : х and consider the region bounded by the curve and the x-axis on [-6, -3]. Then evaluate Vx² – 9 dx. -3 .2 х -6 Be sure  he result is consistent with the graph.

Vx? 9 f(x) : Vx 9 dx. -3 .2 -6

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